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NTA JEE Mains 23rd Jan 2026 Shift 2 - Mathematics

For the following questions answer them individually

Let $$\overrightarrow{a}=\widehat{i}-2\widehat{j}+3\widehat{k}, \overrightarrow{b}=2\widehat{i}+\widehat{j}-\widehat{k}, \overrightarrow{c}=\lambda \widehat{i}+\widehat{j}+\widehat{k}$$ and $$\overrightarrow{v}= \overrightarrow{a} \times \overrightarrow{b}$$. If $$\overrightarrow{v}\cdot\overrightarrow{c}=11$$ and the length of the projection of $$\overrightarrow{b}$$ on $$\overrightarrow{c}$$ is p, then $$9p^{2}$$ is equal to

Bag A contains 9 white and 8 black balls, while bag B contains 6 white and 4 black balls. One ball is randomly picked up from the bag B and mixed up with the balls in the bag A. Then a ball is randomly drawn from the bag A. If the probability, that the ball drawn is white, is $$\dfrac{p}{q},gcd(p,q)=1,$$ then $$p+q$$ is equal to

Let A = {0 ,1,2,...,9}. Let R be a relation on A defined by (x,y) $$\in$$ R if and only if $$\mid x - y \mid $$ is a multiple of 3.

Given below are two statements:

Statement I: $$n (R) = 36.$$
Statement II: R is an equivalence relation.
In the light of the above statements, choose the correct answer from the options given below

Let $$\frac{\pi}{2} < \theta < \pi$$ and $$\cot \theta = -\frac{1}{2\sqrt{2}}$$. Then the value of $$\sin \left(\frac{15\theta}{2}\right) (\cos 8\theta + \sin 8\theta) + \cos \left(\frac{15\theta}{2}\right) (\cos 8\theta - \sin 8\theta)$$ is equal to

Let $$I(x)=\int\frac{3dx}{\left(4x+6\right)\left(\sqrt{4x^{2}}+8x+3\right)}$$ and $$I(0)=\frac{{\sqrt{3}}}{4}+20.$$
If $$I\left( \frac{1}{2} \right)=\frac{a\sqrt{2}}{b}+c, \text { Where a,b,c } \in N,gcd(a,b)=1, \text{ a+b+c is equal to}$$

Let $$\overrightarrow{a},\overrightarrow{b},\overrightarrow{c}$$ be three vectors such that $$\overrightarrow{a}\times\overrightarrow{b}=2(\overrightarrow{a}\times\overrightarrow{c}).$$ If $$ \mid \overrightarrow{a}\mid, \mid\overrightarrow{b}\mid = 4, \mid \overrightarrow{c}\mid = 2,$$ and the angle between $$\overrightarrow{b}$$ and $$\overrightarrow{c}$$ is $$60^{o}$$, then $$\mid\overrightarrow{a}\cdot\overrightarrow{c}$$ is

Let PQ be a chord of the hyperbola $$\frac{x^{2}}{4}-\frac{y^{2}}{b^{2}}=1$$, perpendicular to the x-axis

such that OPQ is an equilateral triangle, O being the centre of the hyperbola. If the eccentricity of the hyperbola is $$\sqrt{3}.$$ then the area of the triangle OPQ is