NTA JEE Mains 23rd Jan 2025 Shift 1

$$\left[Cr(NH_{3})_{5}Cl\right]Cl_{2}$$

$$\left[Cr(NH_{3})_{6}Cl\right]Cl_{3}$$

$$\left[Cr(NH_{3})_{3}Cl_{3}\right]$$

$$\left[Cr(NH_{3})_{4}Cl_{2}\right]Cl$$

Both $$A(OH)_{2}$$ and $$B(OH)_{3}$$ do not show precipitation with $$NH_{4}OH$$

$$A(OH)_{2}$$ will precipitate before $$B(OH)_{3}$$

$$B(OH)_{3}$$ will precipitate before $$A(OH)_{2}$$

$$A(OH)_{2}$$ and $$B(OH)_{3}$$ will precipitate together

$$\int_{268K}^{273K} C_p\,, _{m}{dT} + \frac{\Delta H_{m,\text{fusion}}}{T_f} + \frac{\Delta H_{m,\text{vaporisation}}}{T_b} + \int_{273K}^{373K} C_p\, m\, dT + \int_{373K}^{383K} C_p\, m\, dT$$

$$\int_{268K}^{273K} \frac{C_p\,, m}{T}\, dT + \frac{\Delta H_{m,\text{fusion}}}{T_f} + \frac{\Delta H_{m,\text{vaporisation}}}{T_b} + \int_{273K}^{373K} \frac{C_p.\, m}{T}\, dT + \int_{373K}^{383K} \frac{C_p.\, m dT}{T}$$

$$ \int_{268K}^{383K} C_p\, dT + \frac{q_{\text{rev}}}{T}$$

$$ \int_{268K}^{383K} C_p\, dT + \frac{\Delta H_{\text{melting}}}{273} + \frac{\Delta H_{\text{boiling}}}{373}$$

$$PH_{3}$$ shows lower proton affinity than $$NH_{3}$$.

$$SO_{2}$$ can act as an oxidizing agent, but not as a reducing agent.

$$PF_{3}$$ exists but $$NF_{5}$$ does not.

$$NO_{2}$$ can dimerise easily.

98 .3 mg

48.2 mg

196 .2 mg

150 .4 mg

A-II, B-I, C-III, D-IV

A-II, B-III, C-I, D-IV

A-IV, B-I, C-III, D-II

A-IV, B-III, C-I, D-II

Balmer series, $$\infty \rightarrow 2$$

Lyman series,$$\infty \rightarrow 1$$

Paschen series,$$\infty \rightarrow 3$$

Paschen series,$$5\rightarrow 3$$

$$t_{2} {}_{g} {}^{3}e_{g}{}^{0}$$

$$t_{2} {}_{g} {}^{6}e_{g}{}^{1}$$

$$t_{2} {}_{g} {}^{5}e_{g}{}^{2}$$

$$e^{4}t_{2}{}^{3}$$

q > r > p

r > q > p

q > p > r

p > q > r