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In hydrogen like system the ratio of coulombian force and gravitational force between an electron and a proton is in the order of :
Coulomb force:
$$F_e=\frac{1}{4\pi\epsilon_0}\frac{e^2}{r^2}$$
Gravitational force:lkncoa
$$F_g=\frac{Gm_pm_e}{r^2}$$
Ratio,
$$\frac{F_e}{F_g}=\frac{1}{4\pi\epsilon_0}\frac{e^2}{Gm_pm_e}$$
Using approximate values,
$$\frac{1}{4\pi\epsilon_0}=9\times10^9$$
$$e=1.6\times10^{-19}$$
$$G=6.67\times10^{-11}$$
$$m_p=1.67\times10^{-27}$$
$$m_e=9.1\times10^{-31}$$
Substituting gives order
$$\frac{F_e}{F_g}\sim10^{39}$$
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