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Yes — this question was asking to identify the processes, not compare work/heat.
From the graph, process A is the less steep hyperbola, corresponding to an isothermal process:
$$PV=k$$
For process BBB, the curve is steeper than an isotherm, so it represents an adiabatic process:
$$PV^{\gamma}=k$$
because adiabatic curves are steeper than isotherms on a P-V diagram.
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