If the solution $$y = y(x)$$ of the differential equation $$(x^4 + 2x^3 + 3x^2 + 2x + 2)dy - (2x^2 + 2x + 3)dx = 0$$ satisfies $$y(-1) = -\frac{\pi}{4}$$, then y(0) is equal to:

A

$$\frac{\pi}{2}$$

B

$$-\frac{\pi}{2}$$

C

$$0$$

D

$$\frac{\pi}{4}$$