The statement $$(p \wedge (\sim q)) \Rightarrow (p \Rightarrow (\sim q))$$ is

We need to determine the nature of the statement $$(p \wedge (\sim q)) \Rightarrow (p \Rightarrow (\sim q))$$.

First, simplify $$p \Rightarrow (\sim q) = (\sim p) \vee (\sim q)$$.

So the statement becomes:

$$(p \wedge \sim q) \Rightarrow (\sim p \vee \sim q)$$

$$= \sim(p \wedge \sim q) \vee (\sim p \vee \sim q)$$

$$= (\sim p \vee q) \vee (\sim p \vee \sim q)$$

$$= \sim p \vee q \vee \sim q$$

$$= \sim p \vee T$$

$$= T$$

Since the expression always evaluates to True regardless of the truth values of $$p$$ and $$q$$, this is a tautology.

The answer is Option B: a tautology.