Given below are two statements for the following reaction sequence.

Statement I: Compound 'Z' will give yellow precipitate with NaOI.
Statement II: Compound 'Q' has two different types of'H' atoms (aromatic:aliphatic) in the ratio 1 :3.
In the light of the above statements, choose the correct answer from the options given below:

Compound Z is Acetone ($$CH_3COCH_3$$). Since it is a methyl ketone, it reacts with $$NaOI$$ (Iodoform reagent) to give a yellow precipitate of Iodoform ($$CHI_3$$).

Compound Q is Mesitylene. It has:

• 3 Aromatic 'H' atoms: Located at positions 2, 4, and 6 on the benzene ring.
• 9 Aliphatic 'H' atoms: Located on the three methyl ($$-CH_3$$) groups ($$3 \times 3 = 9$$).
• Ratio: $$3:9$$, which simplifies to $$1:3$$.