Question 61

The sum of all the solutions of the equation $$(8)^{2x} - 16 \cdot (8)^x + 48 = 0$$ is :

Solution

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Let t = 8ˣ: t²-16t+48=0 → t=12,4. x = log₈(12), log₈(4). Sum = log₈(48) = log₈(8×6) = 1+log₈(6).

Option (1).

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