Question 6

The HCF of $$\left(\frac{9}{10},\frac{12}{25},\frac{18}{35},\frac{21}{40} \right)$$ is

HCF of $$\left(\frac{9}{10},\frac{12}{25},\frac{18}{35},\frac{21}{40} \right)$$ = $$\dfrac{\ HCF\left(9,12,18,21\right)}{LCM\left(10,25,35,40\right)}$$. 

Hence, the value = $$\dfrac{3\ }{1400}$$

MAT Quant Questions | MAT Quantitative Ability

MAT DILR Questions | LRDI Questions For MAT

MAT Verbal Ability Questions | VARC Questions For MAT