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In a rhombus, the length of the two diagonals are 40m and 30m respectively. Its perimeter will be
Rhombus has all sides equal and their diagonals bisect each other perpendicularly :
So, Length of each side of rhombus = $$\sqrt{\dfrac{\ d_1^2+d_2^2}{4}}$$
= $$\sqrt{\dfrac{\ 20^2+15^2}{4}}$$
= 25.
Therefore, perimeter of rhombus = 4(l) = 4x25 = 100
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