A Container contains X litres of Milk. A thief stole 50 litres of Milk and replaced it with the same quantity of water. He repeated the same process further two times. And thus, Milk in the container is only X-122 litres. Then what is the quantity of water in the final mixture?

Given, initial volume of milk is X liters.

Now, every time 50 liters of the mixture is taken out and replaced by water, the overall volume will remain X liters only.

So, if final volume of milk is X-122 liters, then volume of water will be X-(X-122) liters = 122 liters

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