Given below are two statements :
Statement I: $$[CoBr_{4}]^{2-}$$ ion will absorb light of lower energy than $$[CoCl_{4}]^{2-}$$ ion.
Statement II: In $$[Col_{4}]^{2-}$$ ion, the energy separation between the two set of d-orbitals is more than $$[CoCl_{4}]^{2-}$$ ion.
ln the light of the above statements, choose the correct answer from the options given below:

In a tetrahedral complex, the splitting of the d-orbitals is denoted by $$\Delta_{t}$$. The energy of light absorbed, $$E_{\text{abs}}$$, is directly proportional to this splitting:
$$E_{\text{abs}} \propto \Delta_{t} \quad-(1)$$

Also, the wavelength of light absorbed, $$\lambda_{\text{abs}}$$, is inversely proportional to the energy absorbed:
$$\lambda_{\text{abs}} \propto \frac{1}{\Delta_{t}} \quad-(2)$$

Ligand field strength for halides follows the order:
$$\text{F}^{-} > \text{Cl}^{-} > \text{Br}^{-} > \text{I}^{-}$$ This means chloride is a stronger field ligand than bromide, and bromide is stronger than iodide.

Analysis of Statement I:
Statement I claims that $$[CoBr_{4}]^{2-}$$ absorbs lower energy light than $$[CoCl_{4}]^{2-}$$. Since $$\Delta_{t}(\text{Cl}^{-}) > \Delta_{t}(\text{Br}^{-})$$ by the ligand field series, then by (1):
$$E_{\text{abs}}(\text{Cl}^{-}) > E_{\text{abs}}(\text{Br}^{-})$$ Hence $$[CoBr_{4}]^{2-}$$ indeed absorbs lower energy light compared to $$[CoCl_{4}]^{2-}$$. Therefore, Statement I is true.

Analysis of Statement II:
Statement II claims that in $$[CoI_{4}]^{2-}$$ the splitting $$\Delta_{t}$$ is greater than in $$[CoCl_{4}]^{2-}$$. From the ligand field series, $$\Delta_{t}(\text{Cl}^{-}) > \Delta_{t}(\text{I}^{-})$$. This contradicts Statement II. Therefore, Statement II is false.

Combining these results: Statement I is true and Statement II is false. Hence the correct answer is Option C.