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Question 52

Match the LIST-I with LIST-II.

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Choose the correct answer from the options given below :

For every species, identify its general electronic feature and hybridisation before matching with the statements in LIST-II.

Case A: Carbocation
A carbocation carries a positive charge on carbon. The carbon is $$sp^2$$ hybridised and possesses an empty $$p$$-orbital that can accept a pair of electrons.
Hence, A corresponds to statement III.

Case B: Carbon-centred free radical
A carbon free radical has one unpaired electron on carbon. Depending on the surrounding atoms it may be $$sp^2$$ or $$sp^3$$ hybridised, but the defining feature is the single unpaired electron.
Hence, B corresponds to statement IV.

Case C: Nucleophile
A nucleophile is a species that donates (supplies) an electron pair to an electron-deficient centre in a reaction.
Hence, C corresponds to statement I.

Case D: Electrophile
An electrophile is electron-deficient; it seeks (receives) an electron pair from a nucleophile.
Hence, D corresponds to statement II.

Collecting the matches:
A - III, B - IV, C - I, D - II.

This is exactly the pairing shown in Option D. Therefore the correct answer is Option D.

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