At steady state the charge on the capacitor, as shown in the circuit below, is $$\mu C$$.

Correct Answer: 16

At steady state capacitor behaves as open circuit.

It is connected in parallel with the $$10Ω$$ resistor, so voltage across capacitor = voltage across $$10Ω$$.

Current in series circuit:

$$I=\frac{5}{10+15}$$

$$=\frac{5}{25}=0.2A$$

Voltage across $$10Ω$$:

V=IR

$$=0.2\times10=2V$$

Charge on capacitor:

Q=CV

$$8\mu F\times2$$

$$=16μC$$

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