Question 50
A wire of resistance $$9\,\Omega$$ is bent to form an equilateral triangle. Then the equivalent resistance across any two vertices will be $$\underline{\hspace{2cm}}\,\Omega.$$
Correct Answer: 2
Solution
Wire of 9Ω bent into equilateral triangle. Equivalent resistance across two vertices.
Each side = 3Ω. Across two vertices: one 3Ω in parallel with two 3Ω in series (6Ω).
$$R_{eq} = \frac{3 \times 6}{3+6} = 2$$ Ω
The answer is 2.
Create a FREE account and get:
- Free JEE Mains Previous Papers PDF
- Take JEE Mains paper tests
