Question 5

A bullet of mass $$50 \text{ g}$$ is fired with a speed $$100 \text{ m/s}$$ on a plywood and emerges with $$40 \text{ m/s}$$. The percentage loss of kinetic energy is :

$$KE_i = \frac{1}{2}(0.05)(100^2) = 250$$ J. $$KE_f = \frac{1}{2}(0.05)(40^2) = 40$$ J.

Loss = $$250 - 40 = 210$$ J. Percentage loss = $$\frac{210}{250} \times 100 = 84\%$$.

The correct answer is Option (1): 84%.

Create a FREE account and get:

Download resources