JEE WhatsApp Group
Sign in
Please select an account to continue using cracku.in
↓ →
JEE WhatsApp Group
Join Our JEE Preparation Group
Prep with like-minded aspirants; Get access to free daily tests and study material.
A body of mass $$1000$$ kg is moving horizontally with a velocity $$6 \text{ m s}^{-1}$$. If $$200$$ kg extra mass is added, the final velocity (in $$\text{m s}^{-1}$$) is:
By conservation of momentum (assuming the extra mass is added with zero velocity in the horizontal direction):
$$m_1 v_1 = (m_1 + m_2)v_f$$
$$1000 \times 6 = (1000 + 200) \times v_f$$
$$6000 = 1200 \times v_f$$
$$v_f = 5 \text{ m s}^{-1}$$
The answer is $$5$$ m/s, which corresponds to Option (4).
Click on the Email ☝️ to Watch the Video Solution
Create a FREE account and get:
Educational materials for JEE preparation
Ask our AI anything
AI can make mistakes. Please verify important information.
AI can make mistakes. Please verify important information.
