Question 5

A body of mass $$1000$$ kg is moving horizontally with a velocity $$6 \text{ m s}^{-1}$$. If $$200$$ kg extra mass is added, the final velocity (in $$\text{m s}^{-1}$$) is:

By conservation of momentum (assuming the extra mass is added with zero velocity in the horizontal direction):

$$m_1 v_1 = (m_1 + m_2)v_f$$

$$1000 \times 6 = (1000 + 200) \times v_f$$

$$6000 = 1200 \times v_f$$

$$v_f = 5 \text{ m s}^{-1}$$

The answer is $$5$$ m/s, which corresponds to Option (4).

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