The average energy released per fission for the nucleus of $$ _{92}^{235}U $$ is 190 MeV.
When all the atoms of 47g pure $$ _{92}^{235}U $$ undergo fission process, the energy released is $$\alpha \times 10^{23}$$MeV. The value of $$\alpha$$ is ______.
(Avogadro Number = 6 $$\times$$ $$10^{23}$$ per mole)