Four capacitors each of capacitance $$16 \mu F$$ are connected as shown in the figure. The capacitance between points A and B is ________ $$\mu F$$.

Correct Answer: 64

Now the given Circuit / figure can be redrawn as

So here all 4 are in parellel

If capacitances are parellel then effective capacitance $$C_{eff}$$ will be

$$C_{eff}=C_1+C_2+C_3+C_4$$

as Capacitancce values are equal to $$C=16\mu\ F$$

$$C_{eff}=4\left(C\right)$$

$$C_{eff}=4\left(16\mu\ \right)F$$

$$C_{eff}=64\mu\ F$$

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