Question 47
10 mole of oxygen is heated at constant volume from $$30^{\circ}CÂ \text{to}Â 40^{\circ}C$$. The change in the internal energy of the gas is ____ cal (the molecular specific heat of oxygen at constant pressure, $$C_{p}= 7 \text{cal}/\text{mol}.^{\circ}C \text{and} R = 2 \text{cal}./\text{mol}.^{\circ}C).$$
Correct Answer: 500
Solution
$$\Delta U = nC_v\Delta T$$. For O₂: $$C_v = C_p - R = 7 - 2 = 5$$ cal/mol.°C.
$$\Delta U = 10 \times 5 \times 10 = 500$$ cal.
The answer is 500.
Create a FREE account and get:
- Free JEE Mains Previous Papers PDF
- Take JEE Mains paper tests
