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We need to find the correct order of ligands arranged in increasing field strength according to the spectrochemical series.
The spectrochemical series (increasing field strength) is:
$$I^- < Br^- < S^{2-} < Cl^- < N_3^- < F^- < OH^- < ox^{2-} < H_2O < NCS^- < CH_3CN < py < NH_3 < en < bipy < phen < NO_2^- < PPh_3 < CN^- < CO < NO^+$$
Check each option:
Option A: $$F^- < Br^- < I^- < NH_3$$ - Incorrect. The order among halides is $$I^- < Br^- < Cl^- < F^-$$, not $$F^- < Br^- < I^-$$.
Option B: $$Br^- < F^- < H_2O < NH_3$$ - This follows the spectrochemical series correctly: $$Br^-$$ is weaker than $$F^-$$, $$F^-$$ is weaker than $$H_2O$$, and $$H_2O$$ is weaker than $$NH_3$$. This is correct.
Option C: $$H_2O < OH^- < CN^- < NH_3$$ - Incorrect. $$CN^-$$ is a stronger field ligand than $$NH_3$$, so $$NH_3 < CN^-$$, not $$CN^- < NH_3$$.
Option D: $$Cl^- < OH^- < Br^- < CN^-$$ - Incorrect. $$Br^-$$ is a weaker field ligand than $$Cl^-$$, so $$Br^-$$ should come before $$Cl^-$$.
The correct answer is Option B.
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