Five persons $$P_{1},P_{2},P_{3},P{4}, \text{and} P_{5}$$ recorded object distance (u) and image distance (v) using same convex lens having powei· +5D as (25,96), (30,62), (35,37), (45,35)
and (50,32) respectively. Identify correct statement

Convex lens with power +5D (focal length f = 1/5 m = 20 cm). Check readings of (u, v) pairs.

Apply lens formula $$\frac{1}{v} - \frac{1}{u} = \frac{1}{f}$$ for each pair:

With $$f = 20$$ cm, $$u$$ is negative (real object), $$v$$ is positive (real image).

For $$P_1$$: $$(u, v) = (-25, 96)$$. $$\frac{1}{96} + \frac{1}{25} = 0.0104 + 0.04 = 0.0504 \approx 0.05 = 1/20$$. Correct.

For $$P_2$$: $$(u, v) = (-30, 62)$$. $$\frac{1}{62} + \frac{1}{30} = 0.0161 + 0.0333 = 0.0495 \approx 0.05$$. Approximately correct.

For $$P_3$$: $$(u, v) = (-35, 37)$$. $$\frac{1}{37} + \frac{1}{35} = 0.0270 + 0.0286 = 0.0556 \neq 0.05$$. INCORRECT. (Expected v: $$\frac{1}{v} = 1/20 - 1/35 = 3/140$$, $$v = 46.67$$).

For $$P_4$$: $$(u, v) = (-45, 35)$$. $$\frac{1}{35} + \frac{1}{45} = 0.0286 + 0.0222 = 0.0508 \approx 0.05$$. Approximately correct.

For $$P_5$$: $$(u, v) = (-50, 32)$$. $$\frac{1}{32} + \frac{1}{50} = 0.03125 + 0.02 = 0.05125 \approx 0.05$$. Approximately correct.

Only $$P_3$$'s reading is significantly off.

The correct answer is Option D: Readings recorded by $$P_3$$ person are incorrect.