The metal that shows highest and maximum number of oxidation state is :

Among the given transition metals, we need to find which shows the highest and maximum number of oxidation states.

Manganese (Mn): Electronic configuration [Ar] $$3d^5 4s^2$$. It shows oxidation states from +2 to +7 (total 6 different oxidation states). The maximum oxidation state is +7 (in $$KMnO_4$$), which equals the total number of 3d + 4s electrons (5 + 2 = 7).

Iron (Fe): [Ar] $$3d^6 4s^2$$. Shows up to +6 (rare). Common: +2, +3.

Cobalt (Co): [Ar] $$3d^7 4s^2$$. Shows up to +4. Common: +2, +3.

Titanium (Ti): [Ar] $$3d^2 4s^2$$. Shows up to +4.

Mn shows the highest maximum oxidation state (+7) and the maximum number of oxidation states among the 3d transition metals.

The correct answer is Option (2): Mn.