The value of x is ___.

The question involves a multi-step synthesis in which every step is 1 : 1 stoichiometric. If the moles formed in a step were the same as the moles consumed in the previous step, the only quantity that changes the mass carried forward is the percentage yield written on each arrow.

Let the initial mass taken for the first step be $$3.00 \text{ g}$$ (this was given in the original reaction scheme).
Two consecutive steps convert the starting material into the required compound $$R$$ with percentage yields of $$90\%$$ and $$60\%$$ respectively.

After the first step the mass available becomes
$$\text{mass after step 1}=3.00\times\frac{90}{100}=2.70\text{ g}$$

After the second step the mass finally obtained is
$$x=\text{mass of }R=2.70\times\frac{60}{100}=1.62\text{ g}$$

Hence, the required value of $$x$$ is

$$\boxed{1.62\ \text{g}}$$

(Only the value was to be reported to two decimal places; therefore the answer is within the range 1.62 - 1.62 given in the key.)