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Question 4

A particle of mass $$m$$ moves on a straight line with its velocity increasing with distance according to the equation $$v = \alpha\sqrt{x}$$, where $$\alpha$$ is a constant. The total work done by all the forces applied on the particle during its displacement from $$x = 0$$ to $$x = d$$, will be :

Work done by all the forces on the particle = change in kinetic energy of the particle

$$KE\ =\ \frac{1}{2}mv^2\ =\ \frac{1}{2}m \left(\alpha \sqrt{\ x}\right)^2\ =\ \frac{1}{2}m\alpha\ ^2x$$

$$KE_{initial}\ =\ 0$$

$$KE_{final}\ =\ \frac{1}{2}m\alpha\ ^2d$$

$$\therefore\ W\ =\ KE_{final}-KE_{initial}\ =\ \frac{1}{2}m\alpha\ ^2d$$

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