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A particle of mass $$m$$ moves on a straight line with its velocity increasing with distance according to the equation $$v = \alpha\sqrt{x}$$, where $$\alpha$$ is a constant. The total work done by all the forces applied on the particle during its displacement from $$x = 0$$ to $$x = d$$, will be :
Work done by all the forces on the particle = change in kinetic energy of the particle
$$KE\ =\ \frac{1}{2}mv^2\ =\ \frac{1}{2}m \left(\alpha \sqrt{\ x}\right)^2\ =\ \frac{1}{2}m\alpha\ ^2x$$
$$KE_{initial}\ =\ 0$$
$$KE_{final}\ =\ \frac{1}{2}m\alpha\ ^2d$$
$$\therefore\ W\ =\ KE_{final}-KE_{initial}\ =\ \frac{1}{2}m\alpha\ ^2d$$
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