A heavy box of mass $$50$$ kg is moving on a horizontal surface. If co-efficient of kinetic friction between the box and horizontal surface is 0.3 then force of kinetic friction is :

Find the kinetic friction force on a 50 kg box on a horizontal surface with $$\mu_k=0.3$$.

The normal force on the horizontal surface is $$N = mg = 50 \times 9.8 = 490$$ N.

From this, the kinetic friction force is $$f_k = \mu_k N = 0.3 \times 490 = 147$$ N.

The correct answer is Option (2): 147 N.

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