A block of mass 5 kg is placed on a rough inclined surface as shown in the figure. If $$\vec{F_1}$$ is the force required to just move the block up the inclined plane and $$\vec{F_2}$$ is the force required to just prevent the block from sliding down, then the value of $$|\vec{F_1}| - |\vec{F_2}|$$ is: [Use $$g = 10$$ m s$$^{-2}$$]

A

$$25\sqrt{3}$$ N

B

$$5\sqrt{3}$$ N

C

$$\frac{5\sqrt{3}}{2}$$ N

D

10 N