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We need to identify the correct order of nucleophilicity from the given options.
Key Principle: A stronger base (more electron-rich species) is generally a better nucleophile when comparing species with the same attacking atom or in the same solvent conditions. Negatively charged species are stronger nucleophiles than their neutral counterparts.
$$F^-$$ is a weaker nucleophile than $$OH^-$$ because fluorine is more electronegative and holds its electron density more tightly. Also, $$F^-$$ is heavily solvated in protic solvents. This order is incorrect.
$$OH^-$$ has a negative charge and is a much stronger nucleophile than neutral $$H_2O$$. This order is incorrect.
$$RO^-$$ (alkoxide ion) is negatively charged and is a much stronger nucleophile than the neutral alcohol $$ROH$$. This order is incorrect.
$$NH_2^-$$ (amide ion) carries a negative charge and has a lone pair readily available for donation. It is a much stronger nucleophile than neutral $$NH_3$$. This order is correct.
The correct answer is Option D: $$NH_2^- > NH_3$$.
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