Match List - I with List - II.

List-I (Si-Compounds)	List-II (Si-Polymeric/Other Products)
A $$(CH_3)_4Si$$	I Chain Silicone
B $$(CH_3)Si(OH)_3$$	II Dimeric Silicone
C $$(CH_3)_2Si(OH)_2$$	III Silane
D $$(CH_3)_3Si(OH)$$	IV 2D-Silicone

Choose the correct answer from the options given below

We need to match each silicon compound with its corresponding product based on the number of hydrolysable groups (OH or Cl groups that can condense).

A. $$(CH_3)_4Si$$ — This compound has no hydroxyl group and no hydrolysable group. It has 4 methyl groups attached to Si. This is simply a silane (tetramethylsilane). So A matches with III (Silane).

B. $$(CH_3)Si(OH)_3$$ — This compound has one methyl group and three $$-OH$$ groups on Si. With three functional groups available for condensation, it can cross-link in multiple directions to form a 2D sheet-like silicone polymer. So B matches with IV (2D-Silicone).

C. $$(CH_3)_2Si(OH)_2$$ — This compound has two methyl groups and two $$-OH$$ groups on Si. Two hydroxyl groups allow condensation in two directions, forming a long chain silicone polymer. So C matches with I (Chain Silicone).

D. $$(CH_3)_3Si(OH)$$ — This compound has three methyl groups and only one $$-OH$$ group on Si. With only one hydroxyl group, two such molecules can condense to form a dimer. So D matches with II (Dimeric Silicone).

The correct matching is: A-(III), B-(IV), C-(I), D-(II)

Hence, the correct answer is Option D.