Sign in
Please select an account to continue using cracku.in
↓ →
Join Our JEE Preparation Group
Prep with like-minded aspirants; Get access to free daily tests and study material.
Match List - I with List - II.
Choose the correct answer from the options given below :
Young’s modulus:
$$Y=\frac{\text{stress}}{\text{strain}}$$
Strain is dimensionless, so
$$[Y]=[\text{stress}]=\frac{\text{Force}}{\text{Area}}=\frac{MLT^{-2}}{L^2}=[ML^{-1}T^{-2}]$$
So, (A) matches with (II)
Torque:
$$\tau=r\times F$$
$$[\tau]=[L]\cdot[MLT^{-2}]=[ML^2T^{-2}]$$
So, (B) matches with (IV)
Coefficient of viscosity:
$$[\eta]=[ML^{-1}T^{-1}]$$
So, (C) matches with (I)
Gravitational constant:
From Newton’s law:
$$F=\frac{GMm}{r^2}\Rightarrow G=\frac{Fr^2}{Mm}$$
$$[G]=\frac{MLT^{-2}\cdot L^2}{M^2}=[M^{-1}L^3T^{-2}]$$
So, (D) matches with (III)
Final matching:
(A)−(II), (B)−(IV), (C)−(I), (D)−(III)
Click on the Email ☝️ to Watch the Video Solution
Create a FREE account and get:
Predict your JEE Main percentile, rank & performance in seconds
Educational materials for JEE preparation
Ask our AI anything
AI can make mistakes. Please verify important information.
AI can make mistakes. Please verify important information.