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We need to find the number of radial and angular nodes in the $$4d$$ orbital.
For the $$4d$$ orbital: principal quantum number $$n = 4$$, azimuthal quantum number $$l = 2$$.
Number of angular nodes = $$l = 2$$
Number of radial nodes = $$n - l - 1 = 4 - 2 - 1 = 1$$
Total number of nodes = $$n - 1 = 3$$
Angular + Radial = $$2 + 1 = 3$$ ✓
The number of radial and angular nodes are $$1$$ and $$2$$, respectively.
The correct answer is Option A: $$1$$ & $$2$$.
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