Sign in
Please select an account to continue using cracku.in
↓ →
Join Our JEE Preparation Group
Prep with like-minded aspirants; Get access to free daily tests and study material.
An antenna is placed in a dielectric medium of dielectric constant $$6.25$$. If the maximum size of that antenna is $$5.0$$ mm, it can radiate a signal of minimum frequency of ______ GHz.
(Given $$\mu_r = 1$$ for dielectric medium)
Correct Answer: 6
An antenna is placed in a dielectric medium with dielectric constant $$\kappa = 6.25$$ and $$\mu_r = 1$$. The maximum size of the antenna is $$5.0$$ mm. We need to find the minimum frequency it can radiate in GHz.
Recall the antenna condition. For a quarter-wave antenna, the minimum antenna length required is one-fourth of the wavelength:
$$l = \frac{\lambda}{4}$$
For the minimum frequency (longest wavelength), the antenna size equals $$\frac{\lambda}{4}$$:
$$\lambda = 4l = 4 \times 5.0 \text{ mm} = 20 \text{ mm} = 0.02 \text{ m}$$
Find the speed of electromagnetic waves in the dielectric medium. The speed in a medium with dielectric constant $$\kappa$$ and relative permeability $$\mu_r$$ is:
$$v = \frac{c}{\sqrt{\kappa \cdot \mu_r}}$$
Substituting the given values:
$$v = \frac{c}{\sqrt{6.25 \times 1}} = \frac{c}{\sqrt{6.25}} = \frac{c}{2.5}$$
$$v = \frac{3 \times 10^8}{2.5} = 1.2 \times 10^8 \text{ m/s}$$
Calculate the minimum frequency using $$v = f\lambda$$:
$$f_{min} = \frac{v}{\lambda} = \frac{1.2 \times 10^8}{0.02}$$
$$f_{min} = 6 \times 10^9 \text{ Hz} = 6 \text{ GHz}$$
The minimum frequency of the signal the antenna can radiate is 6 GHz.
Create a FREE account and get:
Predict your JEE Main percentile, rank & performance in seconds
Educational materials for JEE preparation
Ask our AI anything
AI can make mistakes. Please verify important information.
AI can make mistakes. Please verify important information.