Dimension of $$\dfrac{1}{\mu_0 \varepsilon_0}$$ should be equal to

We know that the speed of light in vacuum is:

$$ c = \frac{1}{\sqrt{\mu_0 \varepsilon_0}} $$

Therefore:

$$ \frac{1}{\mu_0 \varepsilon_0} = c^2 $$

The dimension of $$c$$ (speed) is $$[LT^{-1}]$$.

Therefore, the dimension of $$\frac{1}{\mu_0\varepsilon_0}$$ is:

$$ [c^2] = [L^2T^{-2}] $$

The correct answer is $$L^2 T^{-2}$$.

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