A clock has $$75 \text{ cm}$$ long second hand and $$60 \text{ cm}$$ minute hand respectively. In 30 minutes duration the tip of second hand will travel $$x$$ distance more than the tip of minute hand. The value of $$x$$ in meter is nearly (Take $$\pi = 3.14$$) :

Second hand: in 30 min = 30 revolutions. Distance = 30×2π×0.75 = 45π m.

Minute hand: in 30 min = 0.5 revolution. Distance = 0.5×2π×0.60 = 0.6π m.

x = 45π - 0.6π = 44.4π = 44.4×3.14 = 139.4 m.

The correct answer is Option (3): 139.4.

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