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A radioactive element $$^{242}_{92}$$X emits two $$\alpha$$-particles, one electron and two positrons. The product nucleus is represented by $$^{234}_{P}$$Y. The value of $$P$$ is ______.
Correct Answer: 87
We are given the radioactive element $$^{242}_{92}$$X which emits two $$\alpha$$-particles, one electron ($$\beta^-$$), and two positrons ($$\beta^+$$). The product nucleus is $$^{234}_{P}$$Y.
Effect of each emission on mass number (A) and atomic number (Z):
Each $$\alpha$$-particle ($$^4_2$$He): $$A$$ decreases by 4, $$Z$$ decreases by 2.
Each $$\beta^-$$ (electron): $$A$$ unchanged, $$Z$$ increases by 1 (neutron converts to proton).
Each $$\beta^+$$ (positron): $$A$$ unchanged, $$Z$$ decreases by 1 (proton converts to neutron).
Mass number of product:
$$A_Y = 242 - 2 \times 4 = 242 - 8 = 234 \checkmark$$
Atomic number of product:
$$P = 92 - 2(2) + 1(1) - 2(1) = 92 - 4 + 1 - 2 = 87$$
The value of $$P$$ is $$\boxed{87}$$.
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