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In an open organ pipe $$v_{3}$$ and $$v_{6}$$ are $$3^{rd}$$ and $$6^{th}$$ harmonic frequencies, respectively. If $$v_{6} - v_{3}$$ = 2200 Hz then length of the pipe is ____ mm .
(Take velocity of sound in air is 330 m/s.)
Open organ pipe: $$\nu_n = n\frac{v}{2L}$$. $$\nu_6 - \nu_3 = (6-3)\frac{v}{2L} = \frac{3v}{2L} = 2200$$.
$$L = \frac{3 \times 330}{2 \times 2200} = \frac{990}{4400} = 0.225$$ m = 225 mm.
The answer is Option 4: 225 mm.
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