Question 28

In an open organ pipe $$v_{3}$$ and $$v_{6}$$ are $$3^{rd}$$ and $$6^{th}$$ harmonic frequencies, respectively. If $$v_{6} - v_{3}$$ = 2200 Hz then length of the pipe is ____ mm .
(Take velocity of sound in air is 330 m/s.)

Open organ pipe: $\nu_n = n\frac{v}{2L}$. $\nu_6 - \nu_3 = (6-3)\frac{v}{2L} = \frac{3v}{2L} = 2200$.

$L = \frac{3 \times 330}{2 \times 2200} = \frac{990}{4400} = 0.225$ m = 225 mm.

The answer is Option 4: 225 mm.

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