Resistance of a wire at $$0°C$$, $$100°C$$ and $$t°C$$ is found to be $$10\Omega$$, $$10.2\Omega$$ and $$10.95\Omega$$ respectively. The temperature $$t$$ in Kelvin scale is ________.

Find temperature $$t$$ (in Kelvin) given resistance values at different temperatures.

$$R_t = R_0(1 + \alpha t)$$

At $$t = 100°C$$: $$R_{100} = R_0(1 + 100\alpha)$$

$$10.2 = 10(1 + 100\alpha) \implies 1.02 = 1 + 100\alpha \implies \alpha = \frac{0.02}{100} = 0.0002 \; °C^{-1}$$

$$10.95 = 10(1 + 0.0002t) \implies 1.095 = 1 + 0.0002t \implies t = \frac{0.095}{0.0002} = 475°C$$

$$T = 475 + 273 = 748 \text{ K}$$

The correct answer is 748.