In the given figure an ammeter A consists of a $$240 \Omega$$ coil connected in parallel to a $$10 \Omega$$ shunt. The reading of the ammeter is ___________ mA.

Correct Answer: 160

ammeter = coil (240 Ω) in parallel with shunt (10 Ω)

step 1: equivalent resistance of ammeter

$$RA=\frac{\left(240\times10\right)}{240+10}=\frac{2400}{250}=9.6Ω$$

$$R_{total}=140.4+9.6=150Ω$$

step 3: total current

$$I=\frac{24}{150}=0.16A$$

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