Join WhatsApp Icon JEE WhatsApp Group
Question 25

A point source is emitting sound waves of intensity $$16 \times 10^{-8}$$ W m$$^{-2}$$ at the origin. The difference in intensity (magnitude only) at two points located at distances of 2 m and 4 m from the origin respectively will be ________ $$\times 10^{-8}$$ W m$$^{-2}$$.


Correct Answer: 3

For a point source,

$$I\propto\frac{1}{r^2}$$

Given intensity at source reference (at 1 m, implied) is

$$I_0=16\times10^{-8}\ \text{W/m}^2$$

At r=2m,

$$I_1=\frac{16\times10^{-8}}{2^2}$$

$$=4\times10^{-8}$$

At r=4m,

$$I_2=\frac{16\times10^{-8}}{4^2}$$

$$=1\times10^{-8}$$

Difference in intensity:

$$\left|I_1-I_2\right|$$

$$=(4-1)\times10^{-8}$$

$$=3\times10^{-8}$$

Get AI Help

Video Solution

video

Create a FREE account and get:

  • Free JEE Mains Previous Papers PDF
  • Take JEE Mains paper tests

50,000+ JEE Students Trusted Our Score Calculator

Predict your JEE Main percentile, rank & performance in seconds

Ask AI

Ask our AI anything

AI can make mistakes. Please verify important information.