One cubic metre of iron weighs 7.800 kg. The weight of iron in a pipe of length 4 m, whose interior and exterior diameters measure 10 cm and 12 cm respectively, is nearly

Hollow cylinder Pipe Volume = $$\pi\ \left(R^2-r^2\right)H$$ 

In this case, H = 4 m, R = 6 cm, r = 5 cm.
                   H = 4 m, R = 0.06 m, r = 0.05 m.

So , the volume = $$\dfrac{\ 22}{7}\left(4\right)\left(\ \frac{\ 36-25}{10^4}\right)$$ = $$0.0138\ m^3$$

As one cubic metre of iron weighs 7.8 kg : 
   Total weight of iron of volume $$0.0138\ m^3$$ = 7.8(0.0138) kg = 0.1077 kg

As there is no answer, NTA has dropped this question !!