Question 22
A body of mass $$m$$ is projected with a speed $$u$$ making an angle of $$45°$$ with the ground. The angular momentum of the body about the point of projection, at the highest point is expressed as $$\frac{\sqrt{2}mu^3}{Xg}$$. The value of $$X$$ is
Correct Answer: 8
Create a FREE account and get:
- Free JEE Mains Previous Papers PDF
- Take JEE Mains paper tests
