The amplitude of 15sin(1000$$\pi t$$) is modulated by 10sin(4$$\pi t$$) signal. The amplitude modulated signal contains frequency(ies) of
(A) 500 Hz
(B) 2 Hz
(C) 250 Hz
(D) 498 Hz
(E) 502 Hz
Choose the correct answer from the options given below:

The carrier signal is $$15\sin(1000\pi t)$$, so the carrier frequency is:

$$ f_c = \frac{1000\pi}{2\pi} = 500 \text{ Hz} $$

The modulating signal is $$10\sin(4\pi t)$$, so the signal frequency is:

$$ f_s = \frac{4\pi}{2\pi} = 2 \text{ Hz} $$

In amplitude modulation, the modulated signal contains three frequencies:

1. To begin, carrier frequency, $$f_c = 500$$ Hz (A)

2. Next, lower sideband, $$f_c - f_s = 500 - 2 = 498$$ Hz (D)

3. From this, upper sideband, $$f_c + f_s = 500 + 2 = 502$$ Hz (E)

Therefore, the AM signal contains frequencies A (500 Hz), D (498 Hz), and E (502 Hz).