In AM modulation, a signal is modulated on a carrier wave such that maximum and minimum amplitude are found to be $$6 \text{ V}$$ and $$2 \text{ V}$$ respectively. The modulation index is

In amplitude modulation (AM), the modulation index $$\mu$$ is defined as:

$$\mu = \dfrac{A_{max} - A_{min}}{A_{max} + A_{min}}$$

Given: $$A_{max} = 6 \text{ V}$$ and $$A_{min} = 2 \text{ V}$$.

Substituting:

$$\mu = \dfrac{6 - 2}{6 + 2} = \dfrac{4}{8} = 0.5$$

Converting to percentage:

$$\mu = 0.5 \times 100\% = 50\%$$

Therefore, the correct answer is Option D.

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