Question 20
If 50 Vernier divisions are equal to 49 main scale divisions of a travelling microscope and one smallest reading of main scale is 0.5 mm, the Vernier constant of travelling microscope is:
Solution
50 Vernier divisions = 49 main scale divisions.
1 VSD = $$\frac{49}{50}$$ MSD.
Least count = 1 MSD - 1 VSD = $$1 - \frac{49}{50} = \frac{1}{50}$$ MSD = $$\frac{0.5}{50}$$ mm = $$0.01$$ mm.
The answer is Option (4): $$\boxed{0.01 \text{ mm}}$$.
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