Match List - I with List - II:

List - I	List - II
(a) $$h$$ (Planck's constant)	(i) $$[MLT^{-1}]$$
(b) $$E$$ (kinetic energy)	(ii) $$[ML^2 T^{-1}]$$
(c) $$V$$ (electric potential)	(iii) $$[ML^2 T^{-2}]$$
(d) $$P$$ (linear momentum)	(iv) $$[ML^2 I^{-1} T^{-3}]$$

Choose the correct answer from the options given below:

We need to find the dimensional formula for each quantity in List - I and match it with List - II.

Planck's constant $$h$$ has the dimension of energy multiplied by time. Since energy has dimensions $$[ML^2T^{-2}]$$, we get $$[h] = [ML^2T^{-2}] \times [T] = [ML^2T^{-1}]$$, which matches with (ii).

Kinetic energy $$E = \frac{1}{2}mv^2$$ has dimensions $$[M][LT^{-1}]^2 = [ML^2T^{-2}]$$, which matches with (iii).

Electric potential $$V = \frac{W}{q}$$, where work $$W$$ has dimensions $$[ML^2T^{-2}]$$ and charge $$q$$ has dimensions $$[IT]$$. Therefore $$[V] = \frac{[ML^2T^{-2}]}{[IT]} = [ML^2I^{-1}T^{-3}]$$, which matches with (iv).

Linear momentum $$P = mv$$ has dimensions $$[M][LT^{-1}] = [MLT^{-1}]$$, which matches with (i).

Therefore the correct matching is (a)→(ii), (b)→(iii), (c)→(iv), (d)→(i), which corresponds to Option (1).