A fruit seller has oranges, apples, and bananas in the ratio 3 : 6 : 7. If the number of oranges is a multiple of both 5 and 6, then the minimum number of fruits the seller has is:

A fruit seller has oranges, apples, and bananas in the ratio 3 : 6 : 7.

Let the quantities of oranges, apples, and bananas equal 3k, 6k, and 7k, respectively.

It is given that the number of oranges is a multiple of both 5 and 6.

That means oranges = 5*6*N = 30N

So, if oranges = 30N

Then, apples = 60N

bananas = 70N

The minimum number of fruits the seller has is = 30N+60N+70N = 160N

It depends on the value of N, and the minimum value of N can be 1.

So, minimum number if fruits that seller has = 160.