Question 19

Least count of a vernier caliper is $$\frac{1}{20N}$$ cm. The value of one division on the main scale is 1 mm. Then the number of divisions of main scale that coincide with N divisions of vernier scale is :

Solution

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LC = 1/(20N) cm. MSD = 1mm = 1/10 cm. LC = MSD - VSD. VSD = MSD - LC = 1/10 - 1/(20N) = (2N-1)/(20N) cm. NĂ—VSD = xĂ—MSD. x = NĂ—VSD/MSD = NĂ—(2N-1)/(20N)Ă·(1/10) = (2N-1)/2.

Option (3).

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