The threshold frequency of metal is $$f_0$$. When the light of frequency $$2f_0$$ is incident on the metal plate, the maximum velocity of photoelectron is $$v_1$$. When the frequency of incident radiation is increased to $$5f_0$$, the maximum velocity of photoelectrons emitted is $$v_2$$. The ratio of $$v_1$$ to $$v_2$$ is:

A

$$\frac{v_1}{v_2} = \frac{1}{2}$$

B

$$\frac{v_1}{v_2} = \frac{1}{8}$$

C

$$\frac{v_1}{v_2} = \frac{1}{16}$$

D

$$\frac{v_1}{v_2} = \frac{1}{4}$$