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Let a line L be perpendicular to both the lines
$$L_1: \frac{x + 1}{3} = \frac{y + 3}{5} = \frac{z + 5}{7}$$ and $$L_2: \frac{x - 2}{1} = \frac{y - 4}{4} = \frac{z - 6}{7}$$.
If $$\theta$$ is the acute angle between the lines L and
$$L_3: \frac{x - \frac{8}{7}}{2} = \frac{y - \frac{4}{7}}{1} = \frac{z}{2}$$, then $$\tan\theta$$ is equal to:
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