If frequency of electromagnetic wave is 60 MHz and it travels in air along z direction then the corresponding electric and magnetic field vectors will be mutually perpendicular to each other and the wavelength of the wave in m is:

Find the wavelength of an electromagnetic wave with frequency 60 MHz.

The relationship between speed (c), frequency (f), and wavelength (λ) is given by $$ c = f \times λ \implies λ = \frac{c}{f} $$.

Substituting the speed of light in vacuum c = 3 \times 10^8 m/s and converting the frequency f = 60 MHz = 60 \times 10^6 Hz = 6 \times 10^7 Hz into the formula yields:

$$ λ = \frac{3 \times 10^8}{6 \times 10^7} = \frac{3}{6} \times 10^{8-7} = 0.5 \times 10 = 5 \text{ m} $$.

The correct answer is Option C: 5 m.